please help me answer this, thank you!
Homework Answers
(a) Option B: 2nd plot is correct answer.
(b)
The mean of the sample data is 1247.5
The standard deviation of the sample data is 101.2
Calculations:
(c) Option A : 1st graph is correct answer.
(d) The probability is 0.993
Using MS-EXCEL:
(e)The probability is 0.922
(a) Option B: 2nd plot is correct answer.
(b)
The mean of the sample data is 1247.5
The standard deviation of the sample data is 101.2
Calculations:
(c) Option A : 1st graph is correct answer.
(d) The probability is 0.993
Using MS-EXCEL:
(e)The probability is 0.922
Add Answer to:
please help me answer this, thank you!
In an advertising campaign, a snack company claimed that...
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in an advertising campaign, a snack company claimed that every 18-ounce bag if its cookies contained...
in
an advertising campaign, a snack company claimed that every
18-ounce bag if its cookies contained at least 1000 chocolate
chips.
In an advertising campaign, a snack company claimed that every 18-ounce bag of its cookies contained at least 1000 chocolate chips. Two statisticians attempted verify the claim. The accompanying data represent the number of chips in an 18-ounce bag of the company's cookies based on their sludy Complete parts (a) thre Chocolate Chip Data Table from a normal distribution...
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Suppose a random sample of size 15 is taken from a normal population with mean 25...
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these two questions im having trouble on. Provides the tables for both M 6.2.75 се Use...
these two questions im having trouble on. Provides the tables
for both
M 6.2.75 се Use a standard normal distribution table to obtain the Z-score that has an area of 0.975 to its right. Click here to view page 1 of the normal distribution table, As Click here to view page 2 of the normal distribution table. Za St (Round to two decimal places as needed.) normal distribution page 1 Areas under the standard normal curve Second decimal place in...
z .09 .08 .07 .06 .05 .04 .03 .02 .01 .00 z -3.4 0.0002 0.0003 0.0003 ...
z .09 .08 .07
.06 .05 .04 .03
.02 .01 .00 z
-3.4 0.0002 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 -3.4
-3.3 0.0003 0.0004
0.0004 0.0004 0.0004
0.0004 0.0004 0.0005
0.0005 0.0005 -3.3
-3.2 0.0005 0.0005
0.0005 0.0006 0.0006
0.0006 0.0006 0.0006
0.0007 0.0007 -3.2
-3.1 0.0007 0.0007
0.0008 0.0008 0.0008
0.0008 0.0009 0.0009
0.0009 0.0010 -3.1
-3.0 0.0010 0.0010
0.0011 0.0011 0.0011
0.0012 0.0012 0.0013
0.0013 0.0013 -3.0
-2.9 0.0014 0.0014
0.0015 0.0015 0.0016
0.0016 0.0017 ...
A television sports commentator wants to estimate the proportion of citizens who follow professional football." Complete...
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Problem 7 Question Help * David Polston prints up T-shirts to be sold at local concerts. The T-shirts sell for $24.20 each but cost David only $8.90 each. However, because the T-shirts have concert-specific information on them, David can sell a leftover shirt for only $1.00. Suppose the demand for shirts can be approximated with a normal distribution and the mean demand is 380 shirts, with a standard deviation of 65. Click the icon to view the normal probability table...
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in
an advertising campaign, a snack company claimed that every
18-ounce bag if its cookies contained at least 1000 chocolate
chips.
In an advertising campaign, a snack company claimed that every 18-ounce bag of its cookies contained at least 1000 chocolate chips. Two statisticians attempted verify the claim. The accompanying data represent the number of chips in an 18-ounce bag of the company's cookies based on their sludy Complete parts (a) thre Chocolate Chip Data Table from a normal distribution...
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these two questions im having trouble on. Provides the tables
for both
M 6.2.75 се Use a standard normal distribution table to obtain the Z-score that has an area of 0.975 to its right. Click here to view page 1 of the normal distribution table, As Click here to view page 2 of the normal distribution table. Za St (Round to two decimal places as needed.) normal distribution page 1 Areas under the standard normal curve Second decimal place in...
z .09 .08 .07
.06 .05 .04 .03
.02 .01 .00 z
-3.4 0.0002 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 0.0003
0.0003 0.0003 -3.4
-3.3 0.0003 0.0004
0.0004 0.0004 0.0004
0.0004 0.0004 0.0005
0.0005 0.0005 -3.3
-3.2 0.0005 0.0005
0.0005 0.0006 0.0006
0.0006 0.0006 0.0006
0.0007 0.0007 -3.2
-3.1 0.0007 0.0007
0.0008 0.0008 0.0008
0.0008 0.0009 0.0009
0.0009 0.0010 -3.1
-3.0 0.0010 0.0010
0.0011 0.0011 0.0011
0.0012 0.0012 0.0013
0.0013 0.0013 -3.0
-2.9 0.0014 0.0014
0.0015 0.0015 0.0016
0.0016 0.0017 ...
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