Question

Question 9 (0.5 points) Consider the following hypotheses: Ho: mean = 92 Hy: mean = 92 A test is performed with a sample of size 576. The sample mean was 85.03 and the population standard deviation is 72. Assume that the population is approximately normal. Use the TI- 84 PLUS calculator to compute the P-value. Round your answer to four decimal places (for example: 0.0138). Write only a number as your answer. Your Answer: Answer

Answer 1

Answer: 0.0202

Solution:

We are given

Test is two tailed.

n = 576

Xbar = 85.03

σ = 72

µ = 92

Z = (Xbar - µ)/[σ/sqrt(n)]

Z = (85.03 – 92)/[72/sqrt(576)]

Z = -2.3233

P-value = 0.0202

[By using Ti-84 calculator, use range –infinity to -2.3233 in calculator and then multiply this value by 2, because test is two tailed.]