molarity = (W /MW) (1000 / V inmL)
molarity = 0.65 M
W = 12.5 g
MW = 180 g/mol
V = ?
0.65 = (12.5 / 180) (1000 /V)
1000 / V =9.36
V = 106.84 mL
answer = 106.84 mL
48. What volume of a 0.65 M solution of glucose (C6H12O6) contains 12.5 g of glucose?
A glucose solution contains 51.8 g of glucose (C6H12O6) in 415 g of water. Calculate the freezing point of the solution. (Assume a density of 1.00 g/mL for water.)
1. What mass of 40.0% glucose, C6H12O6, solution contains 75.0 g of water?
a glucose solution contains 51.8 glucose (C6H12O6) in 415 g of water calculate the boiling point of the solution
Consider a solution of glucose (C6H12O6) that was made by combining 25 g of glucose with water. If the resulting solution has a volume of 540 mL, what is the molarity of glucose in the solution? Group of answer choices 0.00026 M 540 M 0.98 M 25 M 0.14 M 46 M 0.044 M 0.54 M 0.26 M 0.046 M 1 M
47. Before you make the solution in #46, you discover a bottle of 7.50 M NaCl solution. What volume of the 7.50 M NaCl solution would you need to use to get the 350 mL of 1.25 M NaCl solution? 48. What volume of a 0.65 M solution of glucose (C6H1206) contains 12.5 g of glucose? Ο Ιο
1. Glucose (C6H12O6, M= 180.16 g/mol) solutions are commercially available. A concentrated sample of an aqueous glucose solution has a density of 1.25 g/mL and contains 55.0 % glucose by mass at 20 °C a) What is the molarity of this glucose solution? b) What is the molality of this solution? c) What is the mole fraction of glucose in this solution?
A solution is prepared by dissolving 28.4 g of glucose (C6H12O6) in 355 g of water. The final volume of the solution is 384 mL . Calculate the solution concentration in each unit. PART A mole fraction x= PART B mole percent = %
A solution is prepared by dissolving 29.2 g of glucose (C6H12O6) in 355 g of water. The final volume of the solution is 376 mL . For this solution, calculate each of the following. A.) molarity B.) moality C. ) percent by mass D.) mole fraction E.) mole percent
Pour 2.5 mL of the 1M glucose (C6H12O6) solution from the flask into the 100 mL volumetric flask. Use the “dilution equation” to determine the volume in mL for the required 0.025M solution, given that the original solution is 1M and you used 2.5 mL Fill the volumetric flask to the 100 mL mark with distilled water. Note: The flask already contains a volume of 2.5 mL. 1. Compute the volume of the diluted 0.025 M solution. 2. What volume...
Determine the vapor pressure of a solution at 25°C that contains 76.6 g of glucose (C6H12O6) in 250.0 mL of water. The vapor pressure of pure water at 25°C is 23.8 torr. Please show work...