Question

47. Before you make the solution in #46, you discover a bottle of 7.50 M NaCl solution. What volume of the 7.50 M NaCl solution would you need to use to get the 350 mL of 1.25 M NaCl solution? 48. What volume of a 0.65 M solution of glucose (C6H1206) contains 12.5 g of glucose? Ο Ιο

Answer 1

47)

use dilution formula

M1*V1 = M2*V2

1---> is for stock solution

2---> is for diluted solution

Given:

M1 = 7.5 M

M2 = 1.25 M

V2 = 350 mL

use:

M1*V1 = M2*V2

V1 = (M2 * V2) / M1

V1 = (1.25*350)/7.5

V1 = 58.3333 mL

Answer: 58.3 mL

Only 1 question at a time please