Question

imestone CCacor)isusedremare acdrc pulluteuts Sem gases is heated to form lime (Ca 0), which reacts wi th Sulfur dioxide t Fom Caldium Sulfe 44 Inside Smokesterc Flues. Assumng a 70 o% 6hat mass of ime eauired to emove all He Sulfur dhoxide ormed bu heCombust on of 9.0x 10 Ka ef coal theot rs Snfur? 6eld tu te overal neachou 4 O.33 mals

Answer 1

CaCO₃(s) $\rightarrow$ CaO(s) + CO₂

CaO(s) + SO₂$\rightarrow$ CaSO₃

S + O₂$\rightarrow$ SO₂

Mass of Sulfur = (0.33/100)×9.0×10⁴kg = 2.97×10² kg = 2.97×10⁵g

The number of moles of SO₂ formed = number of moles of Sulfur = 2.97×10⁵g/32g/mol = 9.28125×10³mol

The number if moles of CaO required = the number of moles of SO₂ formed = 9.28125×10³ mol

= 9.28125×10³mol × 56g/mol

= 5.1975×10⁵ g

= 519.75 kg

The mass of lime (CaO) required = (519.75kg/70.0)×100

= 742.5 kg. (Answer)