Question

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11. What is the empirical formula of a compound that is by mass 50% element A (whose molar mass is 38) and 50% element B (whose molar mass is 19)? A) A,B B) AB, C) AB D) A,B2 12. What would be the volume of 76 g of fluorine gas (molar mass equal to 38 g/mole) at a pressure of 0.821 atm and a temperature of 27°c? R = 0.082 L.atm/molek A) 30 L B) 60 L C) 90 LD ) 600 L

Answer 1

masy of elernent A mas y of element B 50% Lompound mas loog ten mas o Let element A = maus no. of mole of A- 3e 3/mo malan mas no. of meke of A Ina)1.3158 mol maus of element B no. of mole of 6 = 2.6316 moo mas 19 3/me Molan mas 1:2 1.3158 2.631 A B Menue, Empinical formula of compound s Volume ff jas ly 763 maus of Fe jas Ch) moQan mes 3831mel (m) no of mole of fain) Mars 769 3891mo! 2 me melan man Prersune (P) 0.821 atm Tempenature T) L+273] 27 30o K o.082 L.ahm mos k R PV nRT 2malx o.082 Lam mal k x300k o.821 am nRT 60L Volume of F aas 6oL Hentr,