Question

3. Obtain the accepted value from your instructor and calculate the percent error for each result. B-0.200 m QUESTIONS

Concentration (M) Conductivity 7.62 710 0.5 29.1 18.8 0.3 0.25 16.68 8.49 0.1 0.05 4.34 14.19 Conductivity VS. Concentration
Conductivity 7.62 53.9ie x concentrationt 2.5417 5 0783 53.918 x Concentrat ion Concentration Concentration 7.62 O.09418 Cond
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Answer #1

GIVEN :-

Accepted value of concentration :- 0.200 M

FORMULA USED :-

PERCENT ERROR = |{ ( Experimental value - Accepted value) / Accepted value}| *100

CALCULATIONS :-

1. For concentration = 0.09418 M

Percent error =| {(0.09418- 0.200) / 0.200}| *100

= |(0.10582/ 0.2)|*100

=0.5291*100

= 52.91%

2.For concentration = 13.12 M

Percent error = |{(13.12- 0.200) / 0.200}| *100

= |(12.92 / 0.2)|*100

= 64.6*100

= 6460%

3.For concentration = 0.216 M

Percent error = |{(0.216- 0.200) / 0.200}| *100

= |(0.016 / 0.2)|*100

=0.08*100

= 8%

ANS :- Percent Error for concentration = 0.09418 M is 52.91%

Percent Error for concentration = 13.12 M is 6460%

Percent Error for concentration = 0.216 M is 8%

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