GIVEN :-
Accepted value of concentration :- 0.200 M
FORMULA USED :-
PERCENT ERROR = |{ ( Experimental value - Accepted value) / Accepted value}| *100
CALCULATIONS :-
1. For concentration = 0.09418 M
Percent error =| {(0.09418- 0.200) / 0.200}| *100
= |(0.10582/ 0.2)|*100
=0.5291*100
= 52.91%
2.For concentration = 13.12 M
Percent error = |{(13.12- 0.200) / 0.200}| *100
= |(12.92 / 0.2)|*100
= 64.6*100
= 6460%
3.For concentration = 0.216 M
Percent error = |{(0.216- 0.200) / 0.200}| *100
= |(0.016 / 0.2)|*100
=0.08*100
= 8%
ANS :- Percent Error for concentration = 0.09418 M is 52.91%
Percent Error for concentration = 13.12 M is 6460%
Percent Error for concentration = 0.216 M is 8%
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B-0.200 m QUE...
Here are the graphs. instrument should have an absorbance reading of zero when there is no CuS04 present. Print copies of the graph for you and your partner to submit with your lab reports. Calculate the concentration of the unknown using the equation for the line. emros Concentration (M) Absorbance 0.5 1.005 0.3 0.704 0.617 0.25 0.1 0.291 0,05 0.131 0.513 Concentration VS Absorbance 1.2 y 2.1773x R2 0.9566 1 e4e4eeresases4s4 0.8 0.6 0.4 0.2 0.4 0.5 0.6 0.1 0.2...
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B=0.200 m QUESTIONS Concentration (M) Absorbance 0.5 1.005 0.3 0.704 0.25 0.617 0.1 0.291 0.05 0.131 0.513 Concentration VS Absorbance y = 2.1773x R? -0.9566 Absorbance 0.1 0.3 Concentration (M) ? absorbance = 0.513 0.513 = 2.1773x Concentration Concentration concentration - 0.513 2.1773 concentration = (0.2356