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instrument should have an absorbance reading of zero when there is no...
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B-0.200 m QUE...
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B-0.200 m QUESTIONS Concentration (M) Conductivity 7.62 710 0.5 29.1 18.8 0.3 0.25 16.68 8.49 0.1 0.05 4.34 14.19 Conductivity VS. Concentration 35 y53.918x+ 2.5417 R2 0.9954 30 25 20 15 10 5 0 0.1 0.2 0.3 0.4 0.5 0.6 Concentration conductivity un Conductivity 7.62 53.9ie x concentrationt 2.5417 5 0783 53.918 x Concentrat ion Concentration Concentration 7.62 O.09418 Conductivity = 710 710-53. 91...
3. Obtain the accepted value from your instructor and calculate the percent error for each result....
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B=0.200 m QUESTIONS Concentration (M) Absorbance 0.5 1.005 0.3 0.704 0.25 0.617 0.1 0.291 0.05 0.131 0.513 Concentration VS Absorbance y = 2.1773x R? -0.9566 Absorbance 0.1 0.3 Concentration (M) ? absorbance = 0.513 0.513 = 2.1773x Concentration Concentration concentration - 0.513 2.1773 concentration = (0.2356
3. In Part A, you measure the absorbance of four FesCN" solutions and prepare a plot...
3. In Part A, you measure the absorbance of four FesCN" solutions and prepare a plot (Absorbance vs. concentration) similar to the one below. Beer's Law Plot for FeSCN2 0.6 0.5 0.4 0.3 d 0.2 0.1 0 y = 2417.5× + 0.0483 R2 0.99897 0.00025 0.00015 0.0002 0.00005 0.0001 0 Concentration (M) You use this plot as a standard curve in Part B to determine the concentration of an unknown. If an unknown FeSCN2 solution gives an absorbance reading of...
Calibration curve of dilutions 0.6 0.5 y = 8E-05x2 + 0.0189x R2 = 0.99615 0.4 Absorbance...
Calibration curve of dilutions 0.6 0.5 y = 8E-05x2 + 0.0189x R2 = 0.99615 0.4 Absorbance 0.3 0.2 0.1 0 0 5 10 15 20 25 30 Concentration Using this calibration curve, what is the concentration of the sample if the sample has its Absorbance 86.22 HTML Editor
Please help I am completely confused, I included the 2 graphs needed for this post lab....
Please help I am completely confused, I included the 2
graphs needed for this post lab. Thank you!
Postlab Assignments . (a) Using your own standard curve, the line equation you generated and Beer's law equation Equation 1) calculate the molar absorpivity (e) of blue dye. For all your measurem cuvette used is 1.00 cm. Use this as the value of b in Equation 1 ents, the size of (b) Using Beer's law equation again, what does a high value...
please do 1 through 4. Thank you. 0 1. Fe 1.SCN Procedure B: 1. Prepare ICE...
please do 1 through 4. Thank you.
0 1. Fe 1.SCN Procedure B: 1. Prepare ICE tables for beakers 2 - 6 using the example below as a guideline (you will have 5 different ICE tables). Table 3. Sample "ICE" table. Fe(aq)*3 + SCN(aq) = FeSCN2 Initial: **M calculated **M calculated using your Table 2 using your Table 2 volumes volumes Change: - 1x - 1x Equilibrium: M 1x 1x = concentration calculated from Procedure A slope-intercept equation +1x M...
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B-0.200 m QUESTIONS Concentration (M) Conductivity 7.62 710 0.5 29.1 18.8 0.3 0.25 16.68 8.49 0.1 0.05 4.34 14.19 Conductivity VS. Concentration 35 y53.918x+ 2.5417 R2 0.9954 30 25 20 15 10 5 0 0.1 0.2 0.3 0.4 0.5 0.6 Concentration conductivity un Conductivity 7.62 53.9ie x concentrationt 2.5417 5 0783 53.918 x Concentrat ion Concentration Concentration 7.62 O.09418 Conductivity = 710 710-53. 91...
3. Obtain the accepted value from your instructor and calculate the percent error for each result. B=0.200 m QUESTIONS Concentration (M) Absorbance 0.5 1.005 0.3 0.704 0.25 0.617 0.1 0.291 0.05 0.131 0.513 Concentration VS Absorbance y = 2.1773x R? -0.9566 Absorbance 0.1 0.3 Concentration (M) ? absorbance = 0.513 0.513 = 2.1773x Concentration Concentration concentration - 0.513 2.1773 concentration = (0.2356
3. In Part A, you measure the absorbance of four FesCN" solutions and prepare a plot (Absorbance vs. concentration) similar to the one below. Beer's Law Plot for FeSCN2 0.6 0.5 0.4 0.3 d 0.2 0.1 0 y = 2417.5× + 0.0483 R2 0.99897 0.00025 0.00015 0.0002 0.00005 0.0001 0 Concentration (M) You use this plot as a standard curve in Part B to determine the concentration of an unknown. If an unknown FeSCN2 solution gives an absorbance reading of...
Calibration curve of dilutions 0.6 0.5 y = 8E-05x2 + 0.0189x R2 = 0.99615 0.4 Absorbance 0.3 0.2 0.1 0 0 5 10 15 20 25 30 Concentration Using this calibration curve, what is the concentration of the sample if the sample has its Absorbance 86.22 HTML Editor
Please help I am completely confused, I included the 2
graphs needed for this post lab. Thank you!
Postlab Assignments . (a) Using your own standard curve, the line equation you generated and Beer's law equation Equation 1) calculate the molar absorpivity (e) of blue dye. For all your measurem cuvette used is 1.00 cm. Use this as the value of b in Equation 1 ents, the size of (b) Using Beer's law equation again, what does a high value...
please do 1 through 4. Thank you.
0 1. Fe 1.SCN Procedure B: 1. Prepare ICE tables for beakers 2 - 6 using the example below as a guideline (you will have 5 different ICE tables). Table 3. Sample "ICE" table. Fe(aq)*3 + SCN(aq) = FeSCN2 Initial: **M calculated **M calculated using your Table 2 using your Table 2 volumes volumes Change: - 1x - 1x Equilibrium: M 1x 1x = concentration calculated from Procedure A slope-intercept equation +1x M...
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