An attempt at synthesizing a certain optically active compound resulted in a mixture of its enantiomers. The mixtur...

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An attempt at synthesizing a certain optically active compound resulted in a mixture of its enantiomers. The mixture had an o

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Answer 1

Answer #1

let fraction of S enantiomer be x

then fraction of R enantiomer will be 1-x

specific rotation of S enantiomer = 38.9

specific rotation of R enantiomer = -38.9

net rotation = fraction of S enantiomer * specific rotation of S enantiomer + fraction of R enantiomer * specific rotation of R enantiomer

11.7 = x * 38.9 + (1-x) * ( -38.9)

11.7 = x * 38.9 - 38.9 + x * 38.9

77.8*x = 50.6

x = 0.650

so,

fraction of S enantiomer = 0.650

fraction of R enantiomer = 0.350

percentage of S enantiomer = 65.0 %

percentage of R enantiomer = 35.0 %

Answer:

35.0

65.0

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Answer 2

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