Question

Part B Enantiomers If you had a racenic mixture of the two enantiomers mentioned in Part A, what would you expect the specific rotation to be for this mature and WH? Choose one answer from below. ANSWER The specific rolation would be 104.4 degrees because the oplical acdvily af each indvidust enantiomer would be 52.2 degrees The specifie rotation would be zero because the enantiomers would react with one another to create a solution that is not The speciic rotation would be zero because the two enantiomers optically active, willrotate plane polazed ight n equal but 에poate direans tha anotind sch one out and seating a solution that is net opsically active. The specific rotation would be +1044 degrees because the plane polarized light would hit twice as many opéicaly active molecules and rotate twice as much. Part C Enantiomers field because many important molecules are chiraL How could a mixture of enantiomers be separated t isolate one individual enantiomers? Enantiomeric separations is a signiflcent Choose one answer from belew ANSWER: iomars will eacd differenty with other chiral moleues mixture of enantiomers could be separated by a reaction with another chiral compound since enan A micture of enantiomers could be separated with a polarimeter since enantiomers have diflerent optical activiles Amixture of enantiomers could be separated by distilation since different molecules have different boiling points Score Summary: Your score on this ossignment is 15.0%.

Answer 1

Part B - The specific rotation would be zero because the two enantiomers will rotate the plane polarised light in equal butopposite directions thus cancelling each other out and creating a solution that is not optically active.

Part C : would be separated by a reaction with another chiral compound since enantiomers will react differently with other chiral molecules.