Calculate the,energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from n = 4 t...

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Answer 1

Answer #1

The energy difference is given by AE =(-2.18x10-4 f ni = 4, ng =1 AE =(-2.18410, AE =(-2.18x10-18 )( ) AE = (-2.18x10-48 )(1

Wavelength = 0.330 fm = 0.330 x 10-15 m de Broglies equation is i= my where h=6.626x10-34 J.s h 6.626x10-34 J.S 6.626x10-34

Answer 2

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