Question

An electric field is given by E_x = 2.5x³ kN/C. Find the potential difference in kV between the points on the x axis at x = 1 m and x = 5 m.

I got 14 kv but it is wrong. Any suggestions?

Answer 1

The electric field E = 2.5 x³ N / C

Electric potential between the two points ,

           

        

      

        

Magnitude of potential between the point x = 1m   to x = 5m is

V = 0.39 kV

    

Answer 2

Answer 3

we know potencial differnce Δv is

$\Delta V_\mathbf{E} = - \int_C \mathbf{E} \cdot \mathrm{d} \boldsymbol{\ell} \, ,$

= - as x ranges from 1 to 5

= - 2.5 x⁴/4 from 1to 5

= -2.5 (625-1)/4

= -390 kv