The electric field on the x axis due to a point charge fixed at the origin...
The electric field on the x axis due to a point charge fixed at the origin is given by Earrowbolditalic = (b/x2) ihatbold, where b = 5.00 kV·m and x > 0. (a) Find the magnitude and sign of the point charge. (in nC) (b) Find the potential difference between the points on the x axis at x = 1.50 m and x = 2.10 m.
Problem 1 A -2.80 jIC point charge is fixed at the origin of the x axis A-7.80 pC point charge of mass 1.50 grams is moving along the x axis from the "x direction toward the charge at the origin. It has a speed of 22.0 m/s when it is at x -0.800 mIgnore gravity. Calculate (a) the total energy of the-7.80 pC when it is at r-0.800 m. 0.609 (b) the position along the x axis where the speed...
A+2.00 nC point charge is at the origin, and a second -5.00 nC point charge is on the x-axis at x=0.800 m.Part AFind the electric field (magnitude and direction) at the point on the x-axis where x=0.200 m.Part BFind the electric field (magnitude and direction) at the point on the x-axis where x=1.20 m.Part CFind the electric field (magnitude and direction) at the point on the x-axis where x=-0.200 m.
A-4.00 nC point charge is at the origin, and a second -7.00 nC point charge is on the x-axis at x=0.800 mPart AFind the electric field (magnitude and direction) at point on the x-axis at x=0.200 m.Part BFind the electric field (magnitude and direction) at point on the x-axis at x=1.20 m.
A point charge of -4.00 nC is at the origin, and a second point charge of 6.00 nC is on the x axis at x = 0.810 m . Find the magnitude and direction of the electric field at each of the following points on the x axis. A) x=21.0cm B) 1.30m C) -19.0cm
Three point charges are arranged along the x axis. Charge q 1 = -4.20 nC is located at x= 0.220 m and charge q 2 = 2.10 nC is at x= -0.330 m . A positive point charge q 3 is located at the origin. 1)What must the value of q3 be for the net force on this point charge to have magnitude 4.10 μN? 2)Where along the x axis can q3 be placed and the net force on it...
A particular charge distribution produces an electric field along the x-axis of the form, a/x2, where a is a positive constant. Find the expression for potential difference, on the x-axis, between x = A and x = B. That is, find V (B) – V (A). What charge distribution produced this?
A -4.00 nC point charge is at the origin, and a second -5.50 nC point charge is on the x-axis at x = 0.800 m PART A Find the electric field (magnitude and direction) at point on the x-axis at x = 0.200 m. PART B Find the electric field (magnitude and direction) at point on the x-axis at x = 1.20 m. PART C Find the electric field (magnitude and direction) at point on the x-axis at x =...
A +2.00 nC point charge is at the origin, and a second -5.00 nC point charge is on the x-axis at x = 0.800 m. a)Find the electric field (magnitude and direction) at the point on the x-axis where x=0.200 m b)Find the electric field (magnitude and direction) at the point on the x-axis where x=1.200 m c)Find the electric field (magnitude and direction) at the point on the x-axis where x=-0.200 m
Part A Review 1 Constants Find the electric field at the origin, point O. Two point charges are placed on the x axis.(Figure 1)The first charge, g, 8.00 nC, is placed a distance 16.0 m from the origin along the positive x axis, the second charge, 2 6.00 nC, is placed a distance 9.00 m from the origin along the negative x axis Give the x and y components of the electric field as an ordered pair, Express your answer...