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The height of women in the United States is normally distributed with a mean of 165 cm and standard deviation of 7 cm. Show a
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Answer #1

\mu = 165 cm

\sigma = 7 cm

P(X < A) = P(Z < (A - \mu)/\sigma)

P(a randomly selected woman is taller than 167 cm), P(X > 167) = 1 - P(X < 167)

= 1 - P(Z < (167 - 165)/7)

= 1 - P(Z < 0.286)

= 1 - 0.6126

= 0.3874

For a sampling distribution of mean with sample size n = 50,

\mu_\bar{x} = \mu = 165 cm

\sigma_\bar{x} = ulo

= 7/50

= 0.99 cm

P(\bar{x} < A) = P(Z < (A - \mu_\bar{x})/\sigma_\bar{x})

P(a sample of 50 women has an average height greater than 167 cm), P(\bar{x} > 167) = 1 - P(X < 167)

= 1 - P(Z < (167 - 165)/0.99)

= 1 - P(Z < 2.02)

= 1 - 0.9783

= 0.0217

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