Question

A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure below.

Assume that y = 1.23 m and x = 0.546 m. What is the speed of the water coming out of the hole?

The hole has a diameter of 3.64 mm. What is the height, h, of the water level in the tank?

Answer 1

The vertical height y-1.23 m The horizontal distance x = 0.546 m The diameter of the hole d 3.64 mm- 0.00364 m Let depth of the water inside the tank'h' From kinematic equation, S vot (1/2) at2 Here, initial velocity vo-0 m/s The distance S-y The acceleration a = g = 9.8 m/s2 Therefore, above equation becomes, The time t (2y/g) 12 -(2 x1.23 m/9.8 m/s2)12 = 0.5010 s The horizontal exit velocity

= (0.546 m) / (0.5010 s) 1.089 m/s Apply Bernoulli's Law at the tank bottom and tank surface level, (1.089 m/s)2/ (2)(9.8 m/s2) - 0.0605 nm -6.05 cm