A 25.00 mL solution of 0.08050 M NaI is titrated with 0.05000 M AgNO3 . Calculate pAg+ following the addition of the giv...
A 25.00 mL solution of 0.08050 M NaI is titrated with 0.05000 M AgNO3 . Calculate pAg+ following the addition of the given volumes of AgNO3 . The ?sp of AgI is 8.3×10−17 . 35.80 mLpAg+= ?epAg+= 47.90 mLpAg+=
Homework Answers
![• AgNO3 = 0.05m 9) + Nal] - 0.0805 14, 25me ksp = 8.30107 = 0.0805x25 = 2.0125 mmoles AgNO3 = 35.8me. & 35.870.05 = 1.19 mmol](http://img.homeworklib.com/questions/d26c04f0-0947-11ea-ac87-d5df5fc2e008.png?x-oss-process=image/resize,w_560)
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A 25.00 mL solution of 0.08050 M NaI is titrated with 0.05000 M AgNO3 . Calculate pAg+ following the addition of the giv...
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