Question

A 25.00 mL solution of 0.08610 M Nal is titrated with 0.05000 M AgNO . Calculate pAg+ following the addition of the given volumes of AgNO,. The Ksp of Agl is 8.3 x 10-'7. 37.40 mL pAgt = V pAgt = 47.90 mL pAgt =

Answer 1

Anss uen A 25 oom Solution of o.02610 r Nal is tHrated Pith o05000 Ago Calcolate PAgt folla ng the adifich af AaNos The k sp of Agt is 2110 O-the given lolumes Now, Consider a titration veattion as: ANo3aNaleng)Agls)Nanloslog) let's Calculation of uialence poirt We have Ag x VAg Mr XVI VAgt Me v MAg + VAgt o.o 36lo M X 25 00 md O05000 M 2.1535 VAgt O.05000 VAg H3-o5 m Consider dissolution ot Agl as Ag is) Asne)

k sp (AgtJ 33k(0-1 CAst ksp/Cr (a PAgt when 37.Hom silver hitrarte added OBefor quiValence point, alt added Agt ave Consu ed by and Enles vemains nthe Solution We an Calcu late Concentvatin ofl hon veacted as Moles of = original moles of -moles of Aqt added lo.03tomolLJ- l0.034 l00500 w - lo025 omoles laume in L Kmelakity o0 215mol o0o137 mol O000 28 mol olume after addition of 32.Homl AgNo3 - lo-015 +0-0 374) = 00624 L C)No. moles/ olume ot Solution n O000 28 o.0624 O 00 HM8M

Agt s/er Ag3lo Ag 19.5 o M P(Ag log ag] PCAS -13-2) PAt = 13.1 (2) PAgt at quilalence point At Equilaience point all Agt is Consumed by Bul there is squilibrium between solid Ag aud dissolved ons Hence, at quilibriun-the Concentration of Agt iows will be due to disso ciation af Solid /Agt Consider dissolution at Ag as Ags) AstaCag) For above veaction lk sp CAgtJ C :3 x 161

s is the solobilits o Ag then fAgt]. -s( There for e, Sx S2.3 x [o S2.3xl0 1 toe Laue PAgtlog AS PAg Flog (9111 PAST 8-04 PAgt3o PAg hen 47.90 H Silves niterte added Afer zquilalence point, -theve is Excess of Agt ios in -the Solotion Moles ol Ag1 added moles Ag Holes of added Holes of Ast (oo9 L lo0scoo mle lo0250 (003610melL) Moles ol Agt 0.00 239 mol oo 215 mol motes of Ag o000 24mo

Molume ol Solutin aCev additish H7 90m al o05000 M Ag (Nos)1o.025 +0 o479 0.0729 L Nou, No al moles CAgt ol Soluttan in C.000 24ma .0729 L 0.00 2 2921 Agt -lo9 (0.003242) P[Agt -2-48) Pagt 248