Part a) In Maleic acid, there are two titratable protons which are associated with the –COOH group.
Part b) At the endpoint, there should be a sharp change in pH. The endpoint is indicated with the “O” mark in the picture uploaded below.
Part c) We have Henderson- Hasselbach equation,
pH = pKa + log[conjugate base]/[acid]
At the first equivalence point, [conjugate base] = [acid]
Therefore,
pH = pKa1 = 2.1
At the first endpoint (O1), one proton will be deprotonated and AH- will be left.
Therefore, pH = 1/2 (pKa1 + pKa2) = 4.3
At the second equivalence point also, [conjugate base] = [acid]
Therefore,
pH = pKa2 = 6.5
At the second endpoint (O2), both protons will be deprotonated and only A2- is left.
Therefore, pH = 9.5
The titration of Maleic Acid HOOC COOH CC Maleic Acid Hd 20 40 60 Volume of NaOH (mL) The curve above shows the titrat...
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