Question

Suppose a client claims that u(mean) = 7500. You take a sample of n = 49 and you find x = 7200. Assuming that standard deviation = 1200 and is known, can you say at the 0.5 level of significance there is enough evidence that mean is not 7500?

Answer 1

Wolutions Guppose a client cum ihni Received information is goism tu elle 4500 x = 1000 o= 1000 ne (19. Calculate & @ (take the hypothesis - coe have to slate the sun and alternative hypothesis Glere, pull hypothesit is Ho: es = 7500 and, Alternative hypothesis is Ho: 217 7500 Find terst Statistic's in have to obtained the test Statistic 99 cissing given data is, 'Eterer 7-test (statistia is 2= x- o + 200- 7500 T12001 raa]

Ciano 7 .000 11.08 Therefore, Sast (latishgis [1.15) paralee it we have to oblained the prvakie by asing given data is Here, Pelako is P-value=[ 7-test) = [-1.75] pucale 20.0801) Therefore, pvalue =0.0801) O Decisions the too have to compared place and significance a=0.5 is fere, plake <a 0.0801 ♡ 0.5 > Jejected the null bypothes its a+=0.05).

Concasion We have to conclud by coing given date is → Minee xs a enough evidence that mean " at d20.5.