Question

1. Draw Lewis Dot structures for the following: a. O b. Ge c. S-2 d. CO2 e. NF3 f. CC14

Answer 1

Ans) Lewis dot structures shows bonding between the atoms of a molecule and the arrangement of electrons around individual atoms in a molecule.

a) Oxygen has 6 valence electrons, so we write the symbol of oxygen and put 6 dots around it.b) Ge

Germanium, Ge belongs to group 14 and has 4 valence electrons. So, the lewis dot structure of Ge is

c) S²^-

Sulphur belongs to group 16, so it has 6 valence electrons. Sulphide, S²^- has a charge of -2 on it which indicates that it has gained 2 electrons. So, its lewis dot structure is

d) CO₂

4 2- • мріодиt Bu vоlома electrons Xs represents the gained electrons

Carbon has 4 valence electrons and Oxygen has 6 valence electrons. We have to arrange electrons such that the octet of each atom is complete. So, the lewis dot structure is

to::c::: valence elections of C x oy valence electrons of

e) NF₃

Nitrogen has 5 valence electrons and Flourine has 7 valence electrons. So, lewis dot structure of NF₃ is

f) CCl₄

:F: Xhalence electron of N o valence electrons of o

Carbon has 4 valence electrons and Chlorine has 7 valence electrons. So lewis dot structure of CCl4 is

: : Cox Cruce :: x halence elections of e. oy valence elections of cl