(2 points) Calculate the pH of each of the following solutions at 25 oC: 0.250 M HCl 0.250 M NH3 0.250 M C6H5COOH (be...
1. Calculate the pH of a buffer solution prepared by mixing 0.250 L of 0.150 M acetic acid with 0.200 L of 0.250 M sodium acetate. Ka acetic acid = 1.8 x 10-5 Calculate the pH of this solution of after the addition of 0.003 L of 0.200 M HCL 2. Consider a buffer solution prepared by mixing 0.250 L of 0.150 M acetic acid with 0.200 L of 0.250 M sodium acetate. Ka acetic acid = 1.8 x 10-5...
What is the pH of the solution obtained by mixing 30.00 mL of 0.250 M HCl and 30.00 mL of 0.125 M NaOH? We assume additive volumes. What is the pH of a solution that is 0.75 M in sodium acetate and 0.50 M in acetic acid? (ka for acetic acid is 1.3x10-5.) Calculate the pH of a solution prepared by mixing 15.00 ml of 0.10 M NaOH and 30.00 mL of 0.10 M benzoic acid solution. (Benzoic acid is monoprotic; its...
(Please show work) A 100.0 mLbuffer solution is 0.250 M in acetic acid (CH3COOH) and 0.250 M in sodium acetate (CH3COONa). [Acetic Acid (CH3COOH) Ka = 1.8 x 10-5] a)What is the pH of this buffer solution? b)What is the pH after addition of 0.0050 mol of HCl? c)What is the pH after addition of 0.0050 mol of NaOH?
Calculate the pH of the following solutions: 50.0 mL 0.10 M acetic acid + 1.0 mL 1.0 M HCl 50.0 mL 0.10 M acetic acid + 1.0 mL 1.0 M NaOH 50.0 mL 0.10 M sodium acetate + 1.0 mL 1.0 M HCl 50.0 mL 0.10 M sodium acetate + 1.0 mL 1.0 M NaOH 50.0 mL 0.10 M acetic acid/sodium acetate buffer 50.0 mL 0.10 M acetic acid/sodium acetate buffer + 1.0 mL 1.0 M HCl 50.0 mL 0.10...
Calculate the pH of each of the following buffered solutions. K. (HC2H2O2) = 1.8 x 10-5 1.0.19 M acetic acid/0.23 M sodium acetate pH 2.0.23 M acetic acid/0.19 M sodium acetate PH 3. 0.070 M acetic acid/0.18 M sodium acetate PH 4.0.18 M acetic acid/0.070 M sodium acetate PH
a) What is the pH of a solution that consist of 0.20 M ammonia, NH3, and 0.20 M ammonium choride, NH4Cl? (Kb for ammonia is 1.8 x 10-5) b) 1.25 g of benzoic acid (C6H5CO2H) and 1.25 g of sodium benzoate (NaC6H5CO2) are dissolved in enough water to make 250 mL solution. Calculate the pH of the solution using the Handerson-Hasselbach equation (Ka for benzoic acid is 6.3 x 10-5). c) What is the pH after adding 82 mg of...
2. What is the "What is the pH of the solution obtained by mixing 30.00 mL of 0.250 M HCl and 30.00 mL of 0.125 M NaOH? We assume additive volumes. 3. What is the pH of a solution that is 0.75 M in sodium acetate and 0.50 M in acetic acid? (K, for acetic acid is 1.8x10-5.)
4. Calculate the percent ionization and pH of the following solutions: a. 0.175 M NH3 Kg = 1.8 x 10-5. b. 35.0 mL of 0.175 M NH3 is mixed with 15.0 mL of 0.10 M HCl. c. 50.0 mL of 0.275 M acetic acid is mixed with 100. mL of 0.100 M HCl. d. The equivalence point of a 50.0 mL solution of 0.120 M acetic acid titrated by 0.100 M NaOH.
Calculate the pH of each of the following aqueous solutions at 25 °C. (Please help me solve #4 with your work, and check my answers for #1-3, if incorrect please show me why, Thank you) 1) 0.65 M boric acid (B(OH)3, Ka = 7.3 x 10-10) (pH=4.66) 2) 3.15 M ammonia (NH3, Kb = 1.76 x 10-5) (pH= 4.37) 3) 0.82 M benzoic acid (C6H5COOH, Ka = 6.3 x 10-5) (pH=2.14) 4) 0.100 M H3AsO4 (Ka1 = 2.5 x 10-4,...
Calculate the pH at the equivalence point in titrating 0.047 M solutions of each of the following with 0.055 M NaOH. (a) nitric acid (HNO3) pH = (b) acetic acid (HC2H3O2), Ka = 1.8e-05 pH = (c) benzoic acid (HC7H5O2), Ka = 6.3e-05 pH = Calculate the pH at the equivalence point in titrating 0.047 M solutions of each of the following with 0.055 M NaOH. (a) nitric acid (HNO3) pH = (b) acetic acid (HC2H302), Ka = 1.84-05...