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5. Select the compound on each line with the named characteristic and state the reason for your choice: electronegative (a) S
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ANS-5-(a):The effective overlap between orbital's decreases due to large size of p orbital of halides. Hence,electron deficiency of boron atom in its halides follow the trend--BI3>,BBr3,>BCl3>BF3 [NOW THE ORDER OF LEWIS ACID- BBr3,>BCl3>BF3  ] ANS-5(b)-Both bases have electron-releasing groups in ortho and para positions. The ortho-substituted pyridine has more steric repulsion to the trimethylborane[B(CH3 )3 ] and will probably make a less-stable adduct. ********  This means the 4-methyl compound exhibits what could be seen as higher Lewis basicity.******** THANK YOU VERY MUCH .HOPE THIS WILL HELP YOU.GOOD LUCK

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