Question

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(b) Temperature 4th tha YE be canse how can the temperature affect the rate of a reaction 0 V) The following reaction mechanism has been pr reactions (22 ps) proposed for a F 2F fast CFBr, fast (1) What is the overall chemical reaction equation 7 (2) Which are the intermediates 7teet (3) What is the rate law that corresponds to the above mechanism (4) If the overall reaction above is an endothermic reaction. Draw an reaction coordinate (E. vs. R->P) diagra energy versus corresponds to the above mechanism. Indicate the Ea in the diagram. 0 V) For the reaction, 3 N2() +4 0,()6 No, (), in an enclosed vessel, the rate of change of O3(g) is -6.0 atm/min. (1) What is the rate of change of pressure of N2 and that of NO,7 (8 pts) (2) What is the overall rate of change of the pressure in the reaction vessel? (Show the steps of your calculation) -L

Answer 1

(b) The rate rate of a reaction doubles for every 10 °C rise in temperature.

IV) (1) F₂ + CHBr₃ ----> HF + CFBr₃

(2) CBr₃ is the intermediate.

(3) rate = K₂ [F] [CHBr₃​​​​]

Where [F] = 2k₁[F₂]/(2k_-1[F] + k₂[CHBr₃] + k₃[CBr₃])

[CBr₃] = k₂[CHBr₃]/k₃

Therefore, [F] = k₁[F₂]/(k_-1[F] + k₂[CHBr₃])

Hence, rate = k₂k₁[F₂][CHBr₃]/(k_-1[F] + k₂[CHBr₃])

V) (1) The rate of change of pressure of N₂ = 3/4 (-6) = -4.5 atm/min

The rate of change of pressure of NO₂ = 6/4 (6) = 9 atm/min

(2) The overrate of change of pressure in the reaction vessel = (9) - {(-4.5) + (-6)} = 19.5 atm/min