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• CIU TEXAS INSTRUM 2. A 50.00 ml sample of solution containing Fe?ions is titrated with a 0.0216 M KMnO4 solution. It requir
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Answer #1

a) Here

Volume of Fe2+ solution = 50ml

Volume of kMnO4- solution = 20.62ml

Molarity of kMnO4-solution = 0.0216M

Balanced Reaction

MnO + 5Fe2+ + 8H+ + Mn2+ + 5Fe3+ + 4H20

No. of moles of KMnO4 = Molarity x Volume

= 0.0216 x 20.62

= 0.445392 mol.

According to reaction

1 mole of KMnO4 oridises = 5 mol of Fe2+

1.0.445392 mole of KMnO4 oridises = 0.445392 x 5 mol of Fe2+

= 2.22696 moles of Fe2+

Now, Concentration of Fe2+ = 2+ no. of moles Volume

  2.22696 50

  = 0.4453 M

b) Here, Concentration of K2Cr2O7 = 0.0150 M

Cr2O + 6 Fe2+ + 14H+ + 2Cr3+ + 6 Fe3+ + 7H20

Required Volume of K2Cr207 = 24.77ml

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