from equation
5 mol Fe2+ = 1 mol MnO4-
nO of mol of MnO4- required = M*V
= 0.01301*56.15
= 0.73 mmol
No of mol of Fe2+ reacted = 0.73*5 = 3.65 mmol
1 mol Fe2+ = 1 mol Feso4.7H2O
No of mol of melanterite reacted (n)= 3.65*10^-3 mol
n = W/M
w = weight of melanterite reacted = ?
M = molarmass of melanterite = 278 g/mol
3.65*10^-3 = w/278
w = weight of melanterite reacted = 1.015 g
answer: A . 1.015 g
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