3. (a) Calculate the pH of a solution 0.145 M with respect to
CH3CH2COOH and 0.115 M with respect to K+CH3CH2COO-. Ka = 1.3 x 10
– 5 ; pKa = 4.89
(b) Calculate the pH of the same solution after adding 0.015 M
KOH.
(c) Calculate the pH of the same solution as in part (a) but after
addition of 0.015 M HBr.
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3. (a) Calculate the pH of a solution 0.145 M with respect to CH3CH2COOH and 0.115 M with respect to K+CH3CH2COO-. Ka =...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base.Ka of CH3CH2COOH is 1.3 × 10−5.Henderson–Hasselbalch equation: p H = p K a + log [ b a s e ] [ a c i d ]Part a):1) After adding 18.0 mL of the NaOH solution, the mixture is ...
The pH of a 0.20 M propanoic acid (CH3CH2COOH) solution is 2.79. Calculate the Ka of propionic acid.
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5 Henderson-Hasselbalch equation: pH =pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is before the equivalence point on the titration curve. 2) The pH...
Nicole measured the pH of a 0.100 M solution of propanoic acid, CH3CH2COOH, a weak organic acid at equilibrium and found it to be 2.931 at 25C. Calculate the Ka of propanoic acid. Her lab instructor mentions that the half equivalence method is better for determining pKa. What is the half-equivalence point and why is this method better at determining pKa? What is the pH after 20.0 mL of 0.0750 M NaOH is added to 30.0 mL of the 0.100...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 18.0 mL of 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture. Ka of CH3CH2COOH is 1.3 \times × 10−5. Henderson–Hasselbalch equation: LaTeX: pH=pK_a+\log\frac{\left[base\right]}{\left[acid\right]} p H = p K a + log [ b a s e ] [ a c i d ] 2046 HW10 Q1-1.jpg 1) After adding the NaOH...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5. base Henderson-Hasselbalch equation: pH = pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is (Select) equivalence point on the titration curve. 2) The...
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6.)Part B A 64.0 mL volume of 0.25 M HBr is titrated with 0.50 M KOH. Calculate the pH after addition of 32.0 mL of KOH. Express the pH numerically. 7.) Part C Consider the titration of 50.0 mL of 0.20 M NH3 (Kb=1.8×10−5) with 0.20 M HNO3. Calculate the pH after addition of 50.0 mL of the titrant. Express the pH numerically. 8.) Part D A 30.0-mL volume of 0.50 M CH3COOH (Ka=1.8×10−5) was titrated with 0.50 M NaOH....
Part A. Calculate the pH of a buffer solution that is 0.247 M in HCN and 0.171 M in KCN. For HCN, Ka = 4.9×10−10 (pKa = 9.31). Part B. Calculate the pH of a buffer solution that is 0.230 M in HC2H3O2 and 0.170 M in NaC2H3O2. (Ka for HC2H3O2 is 1.8×10−5.) Part C. Calculate the pH of 1.0 L of the original buffer, upon addition of 0.110 mol of solid NaOH.
41.645 -113,30 Calculate the pH of a solution of 0.1M pyridine solution (CHN) with a k) = 1.7 x 10-9 W Colts N 1₂O ² ColH₂NH TOH eek Lase I o.l k, CH, NAD LOH-] [Estoni C -x E .1-x x =LOH 1.7.10-9 = 0.10-0 If the base H, NON has a ky 4.4 X 10", what is the pH of a 0.05M solution of H, NOH? It is known that the K, for ammonia is 1.8 x 10-5 and...