a)
µ = -3.5
σ = 2.1
P( X ≤ -5.18 ) = P( (X-µ)/σ ≤ (-5.18--3.5)
/2.1)
=P(Z ≤ -0.800 ) =
0.2119 (answer)
b)
µ = -3.5
σ = 2.1
P ( X ≥ -0.56 ) = P( (X-µ)/σ ≥ (-0.56--3.5)
/ 2.1)
= P(Z ≥ 1.400 ) = P( Z <
-1.400 ) = 0.0808
(answer)
c)
we need to calculate probability for ,
P ( -5.18 < X <
-0.56 )
=P( (-5.18--3.5)/2.1 < (X-µ)/σ < (-0.56--3.5)/2.1
)
P ( -0.800 < Z <
1.400 )
= P ( Z < 1.400 ) - P ( Z
< -0.800 ) =
0.9192 - 0.2119 =
0.7074 (answer)
d)
proportion= 0.62
Z value at 0.62 =
0.305 (excel formula =NORMSINV(
0.62 ) )
z=(a-µ)/σ
so, a=zσ+µ= 0.305 *
2.1 + -3.5
a = -2.8585 (answer)
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