Question

A man hanging upside down is holding a partner who weighs 475 N. Assume that the patner moves on a circle that has a radius of 6.50 m. At a swinging speed of 4.00m/s, what force must the man apply to his partner in the straight-down position?

Answer 1

Force is given by, F ma (W ac + g 7" Here, a is the centripetal acceleration and W is the weight. Substitute the given values in the above equation 475 N4m/S) +9.8 m/s 475N \((4 m/s) 9.8 m/s6.5 m 594 N Therefore, the force is 594 N