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What will be the heating load for a 6’ x 6’ window constructed of single-pane TD=60 degrees F, Assume U = 1.05. Double-p...

What will be the heating load for a 6’ x 6’ window constructed of single-pane TD=60 degrees F, Assume U = 1.05. Double-pane clear glass, U = 0.55?

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Answer #1

heating load ( Q ) = U * A * TD

where, U - overall heat transfer coefficient

A - Area perpendicular to the heat transfer direction

TD - Temperature difference

\therefore Q = 1.05 * 6 * 6 * 60

= 2268 BTU / hr.

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