The end point of the Zn2+−EDTA titration was observed after 21.50 mL of 0.0500 M EDTA solution was dispensed. Determine the number of moles of zinc ion present in the sample.
number of moles of zinc ion =
The end point of the Zn2+−EDTA titration was observed after 21.50 mL of 0.0500 M EDTA solution was dispensed. Determine...
The end point of a titration was reached after 26.8 mL of 0.4 M disodium EDTA titrant was dispensed into a solution containing the zinc ion. Calculate the moles of disodium EDTA used.
The end point of a titration was reached after 21.3 mL of 0.3 M disodium EDTA titrant was dispensed into a solution containing the zinc ion. Calculate the moles of disodium EDTA used.
Analysis of Aluminum in a Mixture by Solvent Extraction and EDTA Titration. *the amount of EDTA, which is equivalent to the number of moles of zinc and the number of moles of aluminium.* A sample required 9.73 mL of zinc nitrate solution to titrate the EDTA released from aluminum through the addition of fluoride. If the molarity of the zinc solution was 0.025M and EDTA was 0.05M, what was the total weight of the aluminum present in the initial sample?
An unknown solution was analyzed for Ni by an EDTA titration. A 50.00 mL sample of the unknown was treated with 25.00 mL of 0.2404 M EDTA. The excess EDTA was then back titrated with 8.52 mL of 0.0694 M Zn2+ to reach the equivalence point. What was the concentration of Ni (in unit of M) in the 50.00 mL sample? Please keep your answer to three decimal places.
The next 7 questions are related to the titration of 40.0 mL of a 0.0150 M Zn2+ solution with 0.0250 M EDTA in a solution buffered at pH 5. Assume that the temperature is 25 oC and that the formation constant for Zn2+ is 3.13 x 1016 at this temperature. Need help with the last one please! How many mmols of Zn2 are present in the solution before the titration begins? 0.60 mmol You are correct Your receipt no. is...
Question 15 (1 point) Saved If a titration trial requires 10.86 mL of EDTA solution to reach the endpoint, how many moles of CaCO3 are in the sample if the concentration of the iodine solution is 0.003232 M? Your Answer: mol Answer units
A titration was performed to standardize an EDTA solution. a) A 25.00 mL aliquot of a standard solution containing 0.01500 M Ca2+ required 42.87 mL of EDTA to reach the endpoint. The molarity of the EDTA solution is: ________ M b) That same EDTA solution was then used to titrate an unknown hard water sample. A 40.00 mL aliquot of unknown hard water required 34.21 mL of EDTA solution to reach a distinct endpoint. The concentration of Ca2+ ions (assuming...
A 1.000-mL aliquot of a solution containing Cu2* and Ni2+ is treated with 25.00 mL of a 0.04152 M EDTA solution. The solution is then back titrated with 0.02204 M Zn2 solution at a pH of 5. A volume of 16.29 mL of the Zn2+ solution was needed to reach the xylenol orange end point. A 2.000-mL aliquot of the Cu2 and N solution is fed through an ion-exchange column that retains NP. The Cu2" that passed through the column...
The metal ion Mn+ was titrated with 0.0500 M EDTA. The initial solution contained 100.0 mL of 0.0500 M metal ion (Mn+) buffered at a pH of 9.00. a) Calculate the equivalence volume (Veq). b) What is the concentration of the free metal ion at volume V = Veq/2. c) If the conditional formation constant, K’f = 5.4 X 1010, calculate the concentration of free metal ion at volume V = Veq.
1. What is the amount in grams of EDTA you will need to measure out to prepare a 250 mL 0.01 M EDTA solution ? The molar mass of EDTA is 374.27 g/mol. 2. Titration Data from three water samples Water Volume of 0.01 Water Drops of MEDTA Moles Ca2+ sample indicator used to of concentration volume Calmagite reach Ca2+ in water (M) end point source 50 mL4 2 ml USFISA drinking water fountain USF BSF drinking water fountain 50...