Question

say whether its a singlet, doublet, triplet, quartet or aromatic, how many hydrogens it has, and its name

AI bis 26.3.6 H

Answer 1

Let's see index hydrogen deficiency by comparing with saturated hydrocarbon formula -

C_n H_{2 n +2}

n= 8 , so

C₈H _{(2 x8 + 2)}

C₈ H ₁₈

So index hydrogen deficiency = (18-10)/2

= 4

So aromatic ring must be present, it was confirmed by chemical shift of aromatic peak.

¹H NMR pattern -

A) 7.35 ppm ( 5H , multiplet )- aromatic proton

B) 3.9 ppm (2H , quartet )- CH₂  proton deshielded due to vicinity of electronegative oxygen atom .

C) 2.9 ppm (3H , triplets ) - CH₃ proton

Based on index hydrogen deficiency and chemical shift of mentioned proton , compound would be ethoxybenzene.

Let's see predicted structure-

the 629 PPm (3H, Topplets) xx माम ____), निण, (न, पप्पल्स्यो YT. ppy SH)