What is the percent by mass of water in iron(II) sulfate heptahydrate, FeSO_4 7H_2O (or what percent of the mo...

Question

Question

Answer 1

Answer #1

Molar mass of FeSO4.7H2O = 55.845 + 32 + 4 * 16 + 7 * (16+1+1)

=> 55.845 + 32 + 64 + 126

=> 277.845 gm/mol

Mass of water in FeSO4.7H2O = 7 * 18 = 126 gm/mol

Percentage of water as mass = 126/277.845 * 100 = 45.34%

Answer 2

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