What is the molar solubility of PbI2 in 0.10 M KI? Does the presence of KI increase or decrease the solubility of PbI2? You must use the ICE method.
The
equilibrium
is
PbI2 (s) <=>
Pb2+
(aq) + 2 I- (aq)
Ksp=[Pb2+][I-]
=4x^3
but due to presence of KI I- is already present.
hence I-=x+0.1 (as KI is strong electrolyte.)
ksp=8.49*10^-9=x*2(x+0.1)^2
8.49*10^-9=2x*0.01
molar solubility=8.49*10^-7
KI decreased the solubility of PbI2
What is the molar solubility of PbI2 in 0.10 M KI? Does the presence of KI increase or decrease the solubility...
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