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6) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ??Pb2+(aq) + 2I-(aq) A) What is the molar concentration of...

6) The molar solubility of PbI2 is 1.5X10-3 mol/L.

PbI2(s) ??Pb2+(aq) + 2I-(aq)

A) What is the molar concentration of iodide ion in a saturated PbI2 solution?

   Hint: consider mol ratios.

B) Determine the solubility constant, ksp, for lead(II) iodide: ksp = [Pb2+] x [I-]

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Answer #1

PbI2->Pb2+ and 2I-

Molar Concentration of Iodide=2x (1.5x10-3)=3.0x10^-3

Ksp=[Pb][I]^2=(1.5x10^-3)(3.0x10^-3)^2... or 1.35x10^-8=1.4x10^-(in sig. figures)

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