Question

1. The molar solubility of Pbly in water is 1.5x10-mol/L. What is the solubility product of Pblz? answer = What is the molar solubility of Pb(OH)2 in a solution that is 0.010 M NaOH? The Ksp for Pb(OH)2 is 2.8x10-16 answer = 3. CaF2 dissolves in pure water. If the molar solubility of CaF2 is 2.2x10-4 mol/L, what is the concentration of fluoride in solution at equilibrium? answer

Answer 1

1) solubility = 1.5 x 103 mol asi P612 Pb & 22 - s 25 do solubility Product = Rsp = [162] [I-12 - (S) (25) (S)(45%) son = 455 = 4(1.5 x103) 3 21 ' 13.5x109 13.5 Xlo M a 1.35x108 and 1² o konting product of Phil, ksp ( 1.35 x 100 mo (3)

2) Concentration of Naon = 0.010 m key for Pb(OH)2 = 2.8x10 16 Pben a Phett 2014 S 25 8. [P22t] =S [OH-] = 25+ 0.010 from Pb(OH)2 and Naon respectively So Ksp 2 ) (25 + 0.010)2 -) 2.8 x106 - (S) (25+ 0.010) ? As the kap value is very small, then : - (25+0.00)? ~ 6.010) : 2.886" - (S) (0-010)? -) 2-8X10as 104 so 2.8 x 10 12 mnd IL ?, Malax Kaь ту 9 66н, 2- x 16" t/ 3) Molar solubility of cats = 2.2.410 md IL cara - ca 2t & 4- S 25 & [f-]=25 2(2-28 109) mall & 4.4 x 104 mot AL de concentration of smoride des solution is: 4.4 x 10 mol/L
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