Determine the molar solubility of lead (II) iodide, PbI2, in
0.0500 mol/L NaI.
Let x = mol/L of PbI2 that dissolve
This will give us x mol/L Pb2+ and 2x mol/L I-
Ksp of PbI2 = 8.40 x 10^-9
we have arleady some I- : its concentration is 0.0500
M
at equilibrium : [Pb2+]= x and [I-] = 2x + 0.0500
Ksp = [Pb2+][I-]^2 = (x)(2x + 0.0500)^2
x = molar solubility = 3.36 x 10^-6 M
Let x = mol/L of PbI2 that dissolve
This will give us x mol/L Pb2+ and 2x mol/L I-
Ksp of PbI2 = 8.40 x 10^-9
we have arleady some I- : its concentration is 0.0500 M
at equilibrium : [Pb2+]= x and [I-] = 2x + 0.0500
Ksp = [Pb2+][I-]^2 = (x)(2x + 0.0500)^2
x = molar solubility = 3.36 x 10^-6 M
Determine the molar solubility of lead (II) iodide, PbI2, in 0.0500 mol/L NaI.
A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0 x 10^-3 mol/L. a) What is the molar solubility of PbI2? b) Determine the solubility constant, Ksp, for lead(II) iodide. c) Does the molar solubility of lead (II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? EXPLAIN.
1- A saturated solution of lead(II) iodide, PbI2 has an iodide concentration of 3.0*10^-3 mol/L. a- What is the molar solubility of PbI2? b- Determine the solubility constant, Ksp for lead (II) iodide. c- Does the molar solubility of lead(II) iodide increase, decrease or remain unchanged with the addition of potassium iodide to the solution? Explain? 2- The Ksp of Ca(OH)2 was 5.2*10^-6 and 4.8*10^-6 respectively. a- What is the average Ksp of Ca(OH)2?
1) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ? Pb2+(aq) + 2I-(aq) What is the molar concentration of iodide ion in a saturated PbI2 solution in mol/L? Hint: Consider mol ratios. Don't use scientific notation. Use 2 significant figures. ________ 2) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ?Pb2+(aq) + 2I-(aq) Determine the solubility constant, ksp, for lead(II) iodide: ksp = [Pb2+][I-]2 Don't use scientific notation. Use 2 significant figures. ________ 3) How is the molar...
1/ The molar solubility of PbI2 is 1.5 x 10-3 M. a/ What is the molar concentration of iodide ion in a saturated PbI2 solution? b/ Determine the solubility constant, Ksp, for lead(II) iodide 2/ Calculate the molar solubility of PBI2 in the presence of 0.10 M NaI 3/ Compare the molar solubility given in problem 1 and the molar solubility calculated in problem 2. Explain the cause of the difference.
6) The molar solubility of PbI2 is 1.5X10-3 mol/L. PbI2(s) ??Pb2+(aq) + 2I-(aq) A) What is the molar concentration of iodide ion in a saturated PbI2 solution? Hint: consider mol ratios. B) Determine the solubility constant, ksp, for lead(II) iodide: ksp = [Pb2+] x [I-]
A saturated solution of lead (II) iodide, PbI2 has an iodide concentration of 3.0 × 10-3 mol/ L. Calculate the solubility constant, Ksp, for lead (II) iodide. PbI2 (s) ß---à Pb2+(aq) + 2I-(aq) A saturated solution of lead (II) iodide, Pbl2 has an iodide concentration of 3.0 x 10-3 mol/ L. Calculate the solubility constant, Ksp, for lead (II) iodide Pbl2 (s) 8 3.5 x 10-8 5.0 x 10-8 2.8 x 10-8 1.4 x 10-8 -à Pb2 (aq)+2I(aq)
A saturated solution of lead (II) iodide has an iodide ion concentration of 3.0 x 10-3. What is the molar solubility of PbI2? Determine the Ksp for PbI2.
The Ksp of PbI2 is 7.9 x 10-9. What is the molar solubility of lead (II) iodide?
Experiment 22 Prelaborator Molar Solubility, Comm Date Lab Sec. _ Name 1. A saturated solution of lead(II) iodide, Pbl, has an iodide concentration of 3.0 X 10 mol/L (see photo). a. What is the molar solubility of Pl_.? b. Determine the solubility constant, Ko, for lead(II) iodide. c. Does the molar solubility of lead(II) iodide increase, decrease, or remain unchanged with the addition of potassium iodide to the solution? Explain.
Calculate the solubility of lead iodide, PbI2 in units of grams per liter. Ksp(PbI2) = 8.7×10-9. solubility = g/L