the normal boiling point of ethanol is 78.3 deg C and its molar enthalpy of vaporization is 38.56 Kj/mol. what is the ch...

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the normal boiling point of ethanol is 78.3 deg C and its molar enthalpy of vaporization is 38.56 Kj/mol. what is the ch...

the normal boiling point of ethanol is 78.3 deg C and its molar enthalpy of vaporization is 38.56 Kj/mol. what is the change in entropy in the system in J/k when 97.2 grams of ethanol at 1 atm condenses to a liquid at the normal boiling point?

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Answer 1

Answer #1

Boiling point T_b = 78.3^oC = 351.45 K

ΔH = 38.56 kJ/mol = 38560 J/mol

At the boiling point, ΔG = ΔH - T_bΔS = 0

ΔS = ΔH/T_b = 38560/351.45 = 109.7 J/mol.K

Moles of ethanol = mass/molar mass

= 97.2/46.07 = 2.110 mol

Entropy change = moles x ΔS

= 2.110 x 109.7 = 231 J/K

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Answer 2

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the normal boiling point of ethanol is 78.3 deg C and its molar enthalpy of vaporization is 38.56 Kj/mol. what is the ch...

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