The normal boiling point of acetone [(CH3)2CO; MW 58.08 g/mol] is 56.1°C, and its molar enthalpy...

Question

Question

The normal boiling point of acetone [(CH3)2CO; MW 58.08 g/mol] is 56.1°C, and its molar enthalpy of vaporization is 29.1 kJ/mol.

What is the molar entropy of vaporization of 72.3 g of acetone?

molar ΔS_vap = _____ J/(mol•K)

What is the total entropy of vaporization of 72.3g of acetone?

total ΔS_vap = J/K

Answer 1

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Answer #1

sinc so doc= 273K 56.1°C = 273+56-1 = 329.1K since Asvap = Svap = AH T = 29.1. kat mol 3 29.1K = 29100 I 329. Į molok evap =

Answer 2

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