What is [H3O+] in a solution of 0.075 M HNO2 and 0.030 M NaNO2? The pK, of HNO2 is 4.35. 1.8 x 105M 6.0 x 10-M 1.1...

Question

Question

Answer 1

Answer #1

Given:

pKa = 4.35

use:

pH = pKa + log {[conjugate base]/[acid]}

pH = pKa + log {[NO2-]/[HNO2]}

= 4.35+ log {0.030/0.075}

= 3.952

use:

pH = -log [H3O+]

3.952 = -log [H3O+]

[H3O+] = 1.12*10^-4 M

Answer: 1.1*10^-4 M

Answer 2

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