Question

1a. Suppose a hydrogen-oxygen fuel-cell generator was used to produce electricity for a house. Use the balanced redox reactions and the standard cell potential to predict the volume of hydrogen gas (at STP) required each month to generate the electricity needed for a typical house. Assume the home uses 1400 kWh of electricity per month.

1b. Suppose a hydrogen-oxygen fuel-cell generator was used to produce electricity for a house. Use the balanced redox reactions and the standard cell potential to predict the volume of hydrogen gas (at STP) required each month to generate the electricity needed for a typical house. Assume the home uses 1600 kWh of electricity per month.

Answer 1

Solution :- Given that : cas tuh electvitity per month = 1400 -The half cell reactiong in a fuel.cell: Hz. -> 2H+ + Qe o Fo00V og let thé >24420 Eo=1.23 v. Multiply Equation U ya' and add (1) and (1) or +2H2 → 2H2O . Eo zla3 v n =4. (kWh = 3.6 X106 Typical month 31 days. fdos - Qu hours; Total = 31424 - The hours in a month. Phedo kush = 1H00x 3-6x40 = 5.00x109 J AG =nfe) =i 96500 71.23 = 174,780 5/8 moles of the Yeacted = 174, 180 J/a moles of H2

» 5.04 X10 9 I al Energy 1 mol of H2 = above lat stp. Volume of H, 9ae - 5.4 Mo1 ха хәә-4 HTH 780 Qa5,792,000,000 471780 - 4.7 xLot L = = 1600. KWH Electyfcity per Month Month H2 2H+ tae Eo -0.OV Og > UHT the atteo Go - 1.237 ) Multiply Qari (1) X(2) and add c) and oo tat2 QH20 to a las v. n=4 I kwh = 3.6.8106 J Typical month = 31 days. 1 day =du hours..

-Total = 31x2u = 744 hours on a month. 1600 knett = 1600x3.6 *106 = 5.76X1095 AG -DFE Oh x 96.500 X123 = 474780 3/a modes of H₂ = 4.74780 Ila moles of H₂. - 5573109 I of Energy 1 mol of H2 = gaire l at sap 5.76 x 29.4 volume of Hy 24 - 494780 = 258,00 8,000,000 u94780 - Sox 360 ° 2)