The solution of y" = k2y, y(1)=y(-1)=A
is y(x) = _______
The solution of y" = k2y, y(1)=-y(-1)=A
is y(x) = _______
A*e^k/(e^(2k)+1)*e^(k*x)+A*e^k/(e^(2k)+1)*e^(-k*x)
A*e^k/(e^(2k)-1)*e^(k*x)-A*e^k/(e^(2k)-1)*e^(-k*x)
convolution 3. Find a formula for the solution of the initial value problem. (d) y" + k2y: y'(0) f(t), y(0) 1, -1
1. Given that y, - e is a solution of (2x-x') y" +(x-2) y'+2(1-x) y. a. Find the general solution on the interval (2, o). y(3)-1 b. Find a solution of the DE satisfying ¡y(3):0 1. Given that y, - e is a solution of (2x-x') y" +(x-2) y'+2(1-x) y. a. Find the general solution on the interval (2, o). y(3)-1 b. Find a solution of the DE satisfying ¡y(3):0
Given that y=x is a solution of (x2 - x +1)y" - (x2 + x)y' + (x+1)y=0, a linearly independent solution obtained by reducing the order is given by
1. Given that {1,cos x, sin x} is a fundamental solution set for y" + y' = tanx , 0<x<5, find the particular solution using the variation of parameters method.
The solution of y" + y = 2sinx + 3cos x + 1
Problem #1 Y1(x)= x and Y2(x)=e* are linearly independent solution of the homogeneous equation: (x-1)y"-xy'+y = 0 Find a particular solution of (x-1) y”-xy’+y = (x-1)} e2x
1. Let y = f(x) be the solution to the differential equation = y - x. The point (5,1) is on the graph of the solution to this differential equation. What is the approximation for f() if Euler's Method is used, starting at x = 5 with a step size of 0.5?
Wo approximations at x = with the value y(+) of the actual solution. 1. y' = -y, y(O) = 2; y(x) = 2e-x
it y=x+ 1/ / is the general solution of dy dx (y – x)2 +1, then the function v is Select one O a.x²+c 1 o b. x+ C+X cox o d. x + CX e. X + f.c 1 0 8.x²+ c-x? O h-x+c
if y(x) is the solution of dy/dx = (x^(2)+1)/y^(2) y(0)=2 then y(3)=?