if y(x) is the solution of dy/dx = (x^(2)+1)/y^(2)
y(0)=2 then y(3)=?
if y(x) is the solution of dy/dx = (x^(2)+1)/y^(2) y(0)=2 then y(3)=?
Find the solution to the initial value problem: dy dy/dx=x^ 2√1 + x^3/1+cos y y(0)=2 the 1+x^3 is all in square root.
Find a solution of the IVP dy/dx=xy^3(1+x^2)^-1/2, y(0)=1, and give the interval where the solution is defined.
it y=x+ 1/ / is the general solution of dy dx (y – x)2 +1, then the function v is Select one O a.x²+c 1 o b. x+ C+X cox o d. x + CX e. X + f.c 1 0 8.x²+ c-x? O h-x+c
Consider the following system:
dx/dt=y(x^2+y^2-1)
dy/dt= -x(x^2 +y^2-1)
Find the equilibrium solution.
13. Consider the following system dx dy (e) Find the equilibrium solutions (0 Use Maple to sketch a phase portrait (me to understand the qualitative behavior of
13. Consider the following system dx dy (e) Find the equilibrium solutions (0 Use Maple to sketch a phase portrait (me to understand the qualitative behavior of
x dx dy + y) dx dy 0 (b (d a)(c) Answer: (a)
x dx dy + y) dx dy 0 (b (d a)(c) Answer: (a)
Solve the differential equation and use matlab to plot the solution 2. dy +2xy f(x), y(0) = 2 dx f(x)=x0sx<1 l0 x 2 1
Solve the differential equation and use matlab to plot the solution 2. dy +2xy f(x), y(0) = 2 dx f(x)=x0sx
If y=x+ x+ mis is the general solution of dy dx = (y- x)2+1, then the function v is Select one: a. C 1 b. x+ C-X C. X+C d. x2 + c e. -x+ c 1 O f. x2 + x+ 0-1 1 O 8. X+ c+x h. x
explain please
2. Which one of the following DE is exact? a. (x+y)dx+(xy+1) dy=0 b (e + y)<x+ſe+x)dy = 0 c.(ye* +1) dx +(e' + xy) dy = 0 d. (sin x+cos y) dx +(cos x +sin y) dy = 0 e. (eº+1) dx +(e? + 2) dy = 0 3. The solution of the following separable DE xy' =-y? is a. y= '+c b. y=- c. y = In x+c In x+c d. In y=x? + e. yer+C 4....
Please show steps.
Given 3 dy/dx + 2xy^2 = 5x^2 - x + 1, where y(0) = 5 and using a step size of dx = 1, the value of y(1) using Euler's method is most nearly 5.333 1.010 -0.499 17.822 Given 3 dy/dx + 2xy^2 = 5x^2 - x + 1, where y(0) = 5 and using a step size of dx = 1, the value of y(1) using Runge-Kutta 4^th order method is most nearly 5.333 1.010 -0.499...
Q1: Solve the ODE: f) Vyy' + y3/2-1. y(1) = 0. g) (2x +y)dx(2x+y-1)dy 0. i) dx=xy2e": y(2)=0. j) (1 + x*)dy + (1 + y*)dx = 0; y(1) = V3.
Q1: Solve the ODE: f) Vyy' + y3/2-1. y(1) = 0. g) (2x +y)dx(2x+y-1)dy 0. i) dx=xy2e": y(2)=0. j) (1 + x*)dy + (1 + y*)dx = 0; y(1) = V3.