You can determine the volume of fluid that can be contained by a cylindrical tube from the equation V=πr^2L, where r is the radius and L is the length. If r can be measured with a standard deviation of 4%, and L can be measured with a standard deviation of 6%, what is the percent error in the volume? [Report the answer as an integer (i.e., without the % sign and no decimals).]
Volume of a cylinder is given by:
Deviation observed in 'r' = 4%
Deviation observed in L = 6%
We have,
Differentiating both sides we get,
Divide both sides by 'V'
Simplifying further we get,
Plugging in given values we get,
Therefore deviation found in volume is 0.14*100 = 14%
Percent error in the volume is 14.
You can determine the volume of fluid that can be contained by a cylindrical tube from the equation V=πr^2L, where r is...