Question

Al253 (s) + 6H20 (0) --> 2Al(OH)3 (aq) + 3H2S (8) How many grams of H2S will be produced from 30.0 g of Al S3 and 20.0 g of H
0 0
Add a comment Improve this question Transcribed image text
Answer #1

1) According to the reaction,

1 mole Al2S3 require 6 mole H2O

150 g Al2S3 require 108 g H2O

30 g Al2S3 require 108×30/150 g H2O

= 21.6 g H2O

Since we have only 20 g H2O thus, H2O is limiting reagent.

According to the reaction,

6 mole H2O give 3 mole H2S

108 g H2O give 3×34 = 102 g H2S

20 g H2O give 102×20/108 g H2S

= 18.89 g H2S

Please give feedback!

Add a comment
Know the answer?
Add Answer to:
Al253 (s) + 6H20 (0) --> 2Al(OH)3 (aq) + 3H2S (8) How many grams of H2S will be produced from 30.0 g of Al S3 an...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT