Question

Determine the reactions occurring in the following equations

1) Al₂(SO₄)_3(aq) + K₂SO_4(aq) + 24 H₂O_(l) ----> 2KAl(SO₄)₂ * 12H₂O_(s)

2) 2Al_(s) + 2KOH_(aq) +4 H₂SO_4(aq) + 22H₂0_(l) - - - > 2KAl(SO₄)₂*12H₂0_(s) + 3H_2(g)

The following is a bank for the types of reactions that can be occurring. Two or more can be present in one equation.

Metathesis Reactions

Redox Reactions

Single Displacement Reactions

Double Displacement Reactions

Combination Reactions

Decomposition Reactions

Answer 1

Answer:-

Given:-

(1)-

Al₂(SO₄)_3(aq) + K₂SO_4(aq) + 24 H₂O_(l)  $\rightarrow$   2KAl(SO₄)₂.12H₂O_(s)

above reaction reaction can be written as follows:-

Al₂(SO₄)_3(aq) + K₂SO_4(aq) + 24 H₂O_(l)  $\rightarrow$   K₂SO₄.Al₂(SO₄)₃.24H₂O_(s)

aluminium sulfate potassium sulfate water Alum

Above equation is an example of Combination reactions in which two or more substance directly combined to form a single product. therefore in above equation in which aluminium sulfate (Al₂(SO₄)₃) and potassium sulfate (K₂SO₄) directly combined in aqueous medium to form potash alum i.e K₂SO₄.Al₂(SO₄)₃.24H₂O_(s) .

Therefore equation-1 is an example of Combination reactions (i.e the answer)

Given:-

(2)-

2Al_(s) + 2KOH_(aq) + 4 H₂SO_4(aq) + 22H₂O_(l)  $\rightarrow$   2KAl(SO₄)₂.12H₂O_(s) + 3H_2(g)

above reaction reaction can be written in following steps which are given below:-

(I)-

2KOH_(aq) + H₂SO_4(aq)  $\rightarrow$ K₂SO_4(aq) + 2H₂O_(l) -----------------------------------------------------(1)

(II)-

2Al_(s) + 3H₂SO_4(aq)  $\rightarrow$ Al₂(SO₄)_3(aq) + 3H_2(g) ----------------------------------------------------(2)

(III)-

K₂SO_4(aq) + Al₂(SO₄)_3(aq) + 24H₂O_(l)  $\rightarrow$   K₂SO₄.Al₂(SO₄)₃.24H₂O_(s) ----------------------------------------------------(3)

form equation 1 ,2 and 3 we get

2KOH_(aq) + H₂SO_4(aq)  $\rightarrow$ K₂SO_4(aq) + 2H₂O_(l)

2Al_(s) + 3H₂SO_4(aq)  $\rightarrow$ Al₂(SO₄)_3(aq) + 3H_2(g)

K₂SO_4(aq)  + Al₂(SO₄)_3(aq) + 24H₂O_(l)  $\rightarrow$   K₂SO₄.Al₂(SO₄)₃.24H₂O_(s)

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2Al_(s) + 2KOH_(aq) + 4 H₂SO_4(aq) + 22H₂O_(l)  $\rightarrow$   2KAl(SO₄)₂.12H₂O_(s) + 3H_2(g)

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therefore

(I)-

2KOH_(aq) + H₂SO_4(aq)  $\rightarrow$ K₂SO_4(aq) + 2H₂O_(l)

step-I is an example of Double Displacement Reactions in which both reactants exchanged their ions during reaction to form two entirely different products. In above reaction KOH and H₂SO₄ both exchanged their ions ( H⁺ , OH^- , K⁺ SO₄^--) during reactions to form the K₂SO₄ and H₂O.

(II)-

2Al_(s) + 3H₂SO_4(aq)  $\rightarrow$ Al₂(SO₄)_3(aq) + 3H_2(g)

step-II is an example of Single Displacement Reactions and Redox Reactions. It is single displacement reaction because Al_(s) displaced the hydrogen (H) from the H₂SO_4(aq) and it is also redox reaction because oxidation state of Al is changed from 0 to + 3 i.e there is oxidation of Al takes place i.e Al behave as reducing agent whereas oxidation state of H is changed from + 1 to 0 i.e there is reduction of H takes place i.e H behave as oxidizing agent.

(III)-

K₂SO_4(aq)  + Al₂(SO₄)_3(aq) + 24H₂O_(l)  $\rightarrow$   K₂SO₄.Al₂(SO₄)₃.24H₂O_(s)

step-III is an example of Combination reactions in which aluminium sulfate (Al₂(SO₄)₃) and potassium sulfate (K₂SO₄) directly combined in aqueous medium to form potash alum i.e K₂SO₄.Al₂(SO₄)₃.24H₂O_(s) .

Therefore equation-2 is an example of Combination reactions , Single Displacement Reactions , Double Displacement Reactions and Redox Reactions (i.e the answer)