2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g)
What is the limiting reactant, theoretical and percent yield of this equation?
1.03 grams of Al foil
35.10 grams of KOH
15 grams of Sulfuric acid
20 grams of water
the mass of the product is 24.88 grams
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of...
3. How many grams of Alum could form (theoretical yield) when 1.00 g Al (limiting reactant) is used according to the balanced chemical equation given below? 2Al(s) + 2KOH(aq) + 4H2SO4 + 22H2O(1) ► 2KAI(SO4)2:12H2O(s) + 3H2(g)
Which of these two chemicals is the limiting reactant? 4 M KOH 9 M aqueous sulfuric acid (H2SO4) 2.Al (s)+2KOH(aq)+4H2SO4(aq)+22H2O(l) 2K AI(SO4)2 12H20(s)+ ЗНа(9).
how do i find theoretical yield of alum and the percent yield of alum Mass of aluminum foil Mass of 50 mL beaker + alum Mass of 50 mL beaker 1.019 40.99 30.35 10.59 88*C-1030 732-96c Mass of alum Melting point range of pure alum Melting point range of your alum Theoretical yield of alum Percent yield of alum Supporting calculations: The net reaction is: 2Al(s) + 2KOH + 22H2O + 4H2SO4 2KAI(SO4)2-12H2O + 3H2 Theoretical yield of alum Percent...
Determine the reactions occurring in the following equations 1) Al2(SO4)3(aq) + K2SO4(aq) + 24 H2O(l) ----> 2KAl(SO4)2 * 12H2O(s) 2) 2Al(s) + 2KOH(aq) +4 H2SO4(aq) + 22H20(l) - - - > 2KAl(SO4)2*12H20(s) + 3H2(g) The following is a bank for the types of reactions that can be occurring. Two or more can be present in one equation. Metathesis Reactions Redox Reactions Single Displacement Reactions Double Displacement Reactions Combination Reactions Decomposition Reactions
i Supporting calculations: The net reaction is: 2Al(s) + 2KOH + 22H20 + 4H2SO4 → 2KAI(SO4)2:12H20 + 3H2 Theoretical yield of alum 1.01g| I mol All2 mol KAl(SO4)2 #12 H2O1 26.989 Al 2 mol Al 1 mol KAI(SO4)2:12H20
balance the chemical equation Al2(SO4)3(aq)+K2SO4(aq)+24H2O(l)—> 2KAl(SO4)2•12H2O(s)
Chemistry: Which of these two chemicals is the limiting reactant? Grams are not present in the reactant side and I don't know why, I typed the formula straight off of my homework but I can assume Al on the reactant side have the mass 2Al($)+2KOH(aq) +4H2SO4(aq)+22H20(1) +2K AHSO4)2-12 H20(s)+ 3H2(g).
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? Al2(SO4)3(aq) Al(OH)3(s) H2O(l) H2SO4(aq)
This question has to do with an alum synthesis experiment from aluminum, KOH, and H2SO4. The overall reaction is given in equation (1-1): (1-1) 2Al(s) + 2KOH(aq) + 22H2O(l) + 4H2SO4(aq) ---> 2KAl(SO4)2.12H2O(s) + 3H2(g) Note: we used 0.045 moles of H2SO4 and 0.0175 moles of KOH in the experiment. Question 1: Given that KAl(OH)4 was limiting, how many moles of H2SO4 were actually used to form the maximum possible amount of KAl(SO4)2 (Hint: Moles of Al used in this...
Aluminum metal reacts with sulfuric acid according to the following equation: 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(s) + 3H2(g) If 12.9 g of aluminum reacts with excess sulfuric acid, and 62.4 g of Al2(SO4)3 are collected, what is the percent yield of Al2(SO4)3?