This question has to do with an alum synthesis experiment from aluminum, KOH, and H2SO4. The...
This question has to do with an alum synthesis experiment from aluminum, KOH, and H2SO4. The overall reaction is given in equation (1-1):
(1-1) 2Al(s) + 2KOH(aq) + 22H2O(l) + 4H2SO4(aq) ---> 2KAl(SO4)2.12H2O(s) + 3H2(g)
Note: we used 0.045 moles of H2SO4 and 0.0175 moles of KOH in the experiment.
Question 1: Given that KAl(OH)4 was limiting, how many moles of H2SO4 were actually used to form the maximum possible amount of KAl(SO4)2 (Hint: Moles of Al used in this case = 0.0061)?
The correct answer provided by my instructor is 0.012 but I don't understand how to reach that answer. Especially since KAl(OH)4 is not in the overall equation for the reaction we did, so I would appreciate that whoever helps solve this question writes the chemical equation they'll use.
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This question has to do with an alum synthesis experiment from
aluminum, KOH, and H2SO4. The...
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can I please get help solving number 4
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