Which of these two chemicals is the limiting reactant?
4 M KOH
9 M aqueous sulfuric acid (H2SO4)
Which of these two chemicals is the limiting reactant? 4 M KOH 9 M aqueous sulfuric...
2Al(s)+2KOH(aq)+4H2SO4+22H2O(l)→2KAl(SO4)2⦁12H2O(s)+3H2(g) What is the limiting reactant, theoretical and percent yield of this equation? 1.03 grams of Al foil 35.10 grams of KOH 15 grams of Sulfuric acid 20 grams of water the mass of the product is 24.88 grams
Chemistry: Which of these two chemicals is the limiting reactant? Grams are not present in the reactant side and I don't know why, I typed the formula straight off of my homework but I can assume Al on the reactant side have the mass 2Al($)+2KOH(aq) +4H2SO4(aq)+22H20(1) +2K AHSO4)2-12 H20(s)+ 3H2(g).
3. How many grams of Alum could form (theoretical yield) when 1.00 g Al (limiting reactant) is used according to the balanced chemical equation given below? 2Al(s) + 2KOH(aq) + 4H2SO4 + 22H2O(1) ► 2KAI(SO4)2:12H2O(s) + 3H2(g)
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) Which reagent is the limiting reactant when 0.550 mol Al(OH)3 and 0.550 mol H2SO4 are allowed to react? Al2(SO4)3(aq) Al(OH)3(s) H2O(l) H2SO4(aq)
This question has to do with an alum synthesis experiment from aluminum, KOH, and H2SO4. The overall reaction is given in equation (1-1): (1-1) 2Al(s) + 2KOH(aq) + 22H2O(l) + 4H2SO4(aq) ---> 2KAl(SO4)2.12H2O(s) + 3H2(g) Note: we used 0.045 moles of H2SO4 and 0.0175 moles of KOH in the experiment. Question 1: Given that KAl(OH)4 was limiting, how many moles of H2SO4 were actually used to form the maximum possible amount of KAl(SO4)2 (Hint: Moles of Al used in this...
Determine the volume of 0.230 M KOH solution required to neutralize each sample of sulfuric acid. The neutralization reaction is: H2SO4(aq)+2KOH(aq)→ K2SO4(aq)+2H2O(l)Part A25 mL of 0.230 M H2SO4. Express your answer using two significant figures.
Determine the volume of 0.220 M KOH solution required to neutralize each sample of sulfuric acid. The neutralization reaction is: H2SO4(aq)+2KOH(aq)→ K2SO4(aq)+2H2O(l) A.45 mL of 0.220 M H2SO4 B.195 mL of 0.120 M H2SO4 C.45 mL of 0.105 M H2SO4
Determine the volume of 0.215 M KOH solution required to neutralize each sample of sulfuric acid. The neutralization reaction is: H2SO4(ag) + 2KOH(aq) → K2So4(aq) + 2H2O(l)Part A 15 mL of 0.215 M H2SO4Part B 185 mL of 0.105 M H2SO4Part C 40 mL of 0.120 M H2SO4
The balanced equation for the neutralization reaction of aqueous H2SO4 with aqueous KOH is shown. H 2 SO 4 (aq)+2KOH(aq)⟶2 H 2 O(l)+ K 2 SO 4 (aq) What volume of 0.430 M KOH is needed to react completely with 17.6 mL of 0.210 M H2SO4 ? volume: mL
Aluminum hydroxide reacts with sulfuric acid as follows: 2Al(OH)3(s)+3H2SO4(aq)→Al2(SO4)3(aq)+6H2O(l) a. Which reagent is the limiting reactant when 0.450 mol Al(OH)3 and 0.450 mol H2SO4 are allowed to react? b. How many moles of Al2(SO4)3 can form under these conditions? c. How many moles of the excess reactant remain after the completion of the reaction?