Given:
pOH = 9.60
use:
PH = 14 - pOH
= 14 - 9.60
= 4.40
use:
pH = -log [H+]
4.40 = -log [H+]
[H+] = 3.981*10^-5 M
use:
pOH = -log [OH-]
9.60 = -log [OH-]
[OH-] = 2.512*10^-10 M
Answers:
pH = 4.40
[H+] = 4.0*10^-5 M
[OH-] = 2.5*10^-10 M
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