H2So4 is strong acid . it is completely ionizable
H2SO4(aq) ----------> H^+ (aq) + HSO4^- (aq)
10.1M ------------- 10.1M ---------- 10.1M
HSO4^-(aq) ------------> H^+ (aq) + SO4^2- (aq)
I 10.1 10.1 0
C -x +x +x
E 10.1-x 10.1+x +x
Ka = [H^+][SO4^2-]/[HSO4^-]
1.2*10^-2 = (10.1+x)x/(10.1-x)
1.2*10^-2*(10.1-x) = (10.1+x)x
x = 0.012
[H^+] = 10.1 + x = 10.1 + 0.012 = 10.112
PH = -log[H^+]
= -log10.112
= -1.00 >>>>answer
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